(2x+3y)(5x^2-7x+4)=0

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Solution for (2x+3y)(5x^2-7x+4)=0 equation: 


Simplifying
(2x + 3y)(5x2 + -7x + 4) = 0

Reorder the terms:
(2x + 3y)(4 + -7x + 5x2) = 0

Multiply (2x + 3y) * (4 + -7x + 5x2)
(2x * (4 + -7x + 5x2) + 3y * (4 + -7x + 5x2)) = 0
((4 * 2x + -7x * 2x + 5x2 * 2x) + 3y * (4 + -7x + 5x2)) = 0
((8x + -14x2 + 10x3) + 3y * (4 + -7x + 5x2)) = 0
(8x + -14x2 + 10x3 + (4 * 3y + -7x * 3y + 5x2 * 3y)) = 0

Reorder the terms:
(8x + -14x2 + 10x3 + (-21xy + 15x2y + 12y)) = 0
(8x + -14x2 + 10x3 + (-21xy + 15x2y + 12y)) = 0

Reorder the terms:
(8x + -21xy + -14x2 + 15x2y + 10x3 + 12y) = 0
(8x + -21xy + -14x2 + 15x2y + 10x3 + 12y) = 0

Solving
8x + -21xy + -14x2 + 15x2y + 10x3 + 12y = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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